The two blocks shown are originally at rest. Neglecting the masses of the pulleys determine the tension in the cable.

Given: $\{Wa,Wb,u\}=\{235\mathrm{.}75,165\mathrm{.}45,0\mathrm{.}59\}$

Weight of block $A=235\mathrm{.}75lbs$

Weight of block $B=165\mathrm{.}45lbs$

kinetic friction coefficient $=0\mathrm{.}59$

Find:

Tension in cable $=q,$ Ibs