The two sides of the DNA double helix are connected by base pairs (adenine, thymine, cytosine, and guanine). Due to the geometric shape of the molecules, adenine bonds with thymine, and cytosine with guanine. The figure shows the thymine-adenine bond. Each electric charge shown is "e", and the distance HN is 0.110 nm. The value of "e" is equal to 1.6x10-19C.

Part A

Calculate the net force that thymine exerts on adenine. To keep the calculations fairly simple, yet reasonable, consider only the forces due to the O−H−Nand the N−H−N combinations, assuming that these two combinations are parallel to each other. Remember, however, that in the O−H−N set, the O−exerts a force on both the H+ and the N−, and likewise along the N−H−N set.

B) is the net force attractive or repulsive?

c) calculate the force on the electron in the hydrogen Atom, which is 5.29×10^-2 nam from the proton

d) compare the strength of the bonding form of the electron in the hydrogen with the bonding force of the adenine thymine molecules

Transcribed Image Text:

H H Timina H 0.280 ( nm Adenina H (N) + H H 0.300 nm N H N + (N) N H H H Timina H 0.280 ( nm Adenina H (N) + H H 0.300 nm N H N + (N) N H