The ultimate bearing pressure can be derived from a modified version of Terzaghi's equation for square pad footings:

$q_u=1\mathrm{.}3c{N}_c+q{N}_q+0\mathrm{.}4B{N}_{}$

Your group's soil friction angle $=22$

From Figure $4,$ the bearing capacity factors:

Cohesion factor $N_c=5.77$

Overburden factor $N_q=$ T $$

Unit weight factor $N_{}=0$

The unit weight $$ is the force equivalent of the soil density $$ :Conventionally, the unit weight is expressed with the units $[$kN$//$m$^(3)].$ To convert the unit weight:

Unit weight $[k\frac{N}{m^3}]=\frac{\text{U}\text{n}\text{i}\text{t}\text{w}\text{e}\text{i}\text{g}\text{h}\text{t}[\frac{N}{m^3}]}{1000}=\frac{1650\frac{N}{m^3}}{1000}=16\mathrm{.}5k\frac{N}{m^3}$

As Module $8$ notes, the overburden pressure $q($written as ${}_v$ in Module $8)$ depends on the soil unit weinht $v$ and the depth of the footing base $D$ :

Combining all the terms in the modified Terzaghi's equation:

$q_u=1\mathrm{.}3c{N}_c+q{N}_q+0\mathrm{.}4B{N}_{}=$

$=(1\mathrm{.}3155\mathrm{.}7)+(9\mathrm{.}98)+(0\mathrm{.}4B16\mathrm{.}50)$

$=190\mathrm{.}3+39\mathrm{.}6B$

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Tutorial Three