the values you need to plug in. = 2 per 8 hour workday.

u = 8 machines workday

sorry i couldnt get both symbols in the same picture so i did my best to imitate them.

virginia's Ron Mcpherson electronics corporation retains a service cre to repair machine breakdowns that occut on an average of =2 per 8-hour workday (approximately poisson in nature). The crew can service an average of u = 8 machines per workfay, with a repair tune distribution that resembles the negative exponential distrubution.

Erginia's Ron McPherson Electronics Corporation retains a service crew to repair machine breakdowns that occur on an average of 2 = 2 per 8-hour w 10 machines per workday, with a repair time distribution that resembles the negative exponential distribution: ) The utilization rate of this service system -0.20 fround your response to two decimal places) ) The average downtime for a broken machine - 0.13 days (round your response to two decimal places) 5) The average number of machines waiting to receive service at any given time = 0.050 machines (round your response to three decimal places) d) The probability that there is more than one machine that is in the system = 0.040 (round your response to three decimal places) The probability that there are more than two machines that are in the system = 0.008" fround your response to throw decimal placna). The probability that there are more than three machines that are in the system = 0.002 round your response to three decimal places) The probability that there are more than four machines that are in the system = 0.000 (round your response to three decimal places)