There are 100 centimeters in a meter, 2.54 centimeters in an inch, 12 inches in a...

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There are 100 centimeters in a meter, 2.54 centimeters in an inch, 12 inches in a foot, 3 feet in a yard, and 1760 yards in a mile. 1) 2) 20DI TAM A race is 6.2 miles long. Use conversion factors and dimensional analysis to determine the length of the race measured in: a) yards. b) Tmile = 1760 yards. 6.2x1760 =10912 yards meters. -1 mile = 1609.34 meters 6.2x1609.34-9977.931 One of the events at a swim meet is the 500 meter freestyle. Use conversion factors and dimensional analysis to determine the length of this race in: a) feet. 1 meter = 3.28084 feet meters 500 meter = 3.28084 X 500 Feet = b) miles. (1640.42 A 1 meter =.000621371 miles 500 meter = .000 621371 X500 = (10.31 miles 6) 7) 8) Now place the numbers into your set-up and simplify. How many feet will you travel in 3 seconds if you are driving 55 miles per hour? (There may be some numbers that you will need to look up in order to be sure that the numerator and denominator in each fraction are of equivalent value.) How close was your prediction in question #3? Suppose that most distractions take between 1 and 5 seconds. Incorporate this information into your original dimensional analysis strategy and find a range for the number of feet you might travel at 55 mph if you are distracted. Suppose you were driving 70 miles per hour on the highway. How many feet would you travel if you were distracted for 5 seconds? (Show the full conversion.) There are 100 centimeters in a meter, 2.54 centimeters in an inch, 12 inches in a foot, 3 feet in a yard, and 1760 yards in a mile. 1) 2) 20DI TAM A race is 6.2 miles long. Use conversion factors and dimensional analysis to determine the length of the race measured in: a) yards. b) Tmile = 1760 yards. 6.2x1760 =10912 yards meters. -1 mile = 1609.34 meters 6.2x1609.34-9977.931 One of the events at a swim meet is the 500 meter freestyle. Use conversion factors and dimensional analysis to determine the length of this race in: a) feet. 1 meter = 3.28084 feet meters 500 meter = 3.28084 X 500 Feet = b) miles. (1640.42 A 1 meter =.000621371 miles 500 meter = .000 621371 X500 = (10.31 miles 6) 7) 8) Now place the numbers into your set-up and simplify. How many feet will you travel in 3 seconds if you are driving 55 miles per hour? (There may be some numbers that you will need to look up in order to be sure that the numerator and denominator in each fraction are of equivalent value.) How close was your prediction in question #3? Suppose that most distractions take between 1 and 5 seconds. Incorporate this information into your original dimensional analysis strategy and find a range for the number of feet you might travel at 55 mph if you are distracted. Suppose you were driving 70 miles per hour on the highway. How many feet would you travel if you were distracted for 5 seconds? (Show the full conversion.)