Question: Therefore the linearized equation of motion is: ml 2 + c + mgl ( sin 0 + cos 0 ) = u ( t )

Therefore the linearized equation of motion is:
ml2 + c + mgl(sin 0+ cos 0 )= u(t)(1)
(a) Find all equilibrium points of the non-linear system (i.e. given eq.(1) and = = = u(t)=0
solve for all 0). Compute the transfer function G(s)= (s)
U (s) for each equilibrium point and determine
if the LTI approximation of the pendulum near the equilibrium is stable or unstable.
(b) Create a non-linear model of the pendulum and a linear model of the pendulum (linearized at 0=0)
in Simulink.
(c) With an initial condition of the pendulum hanging down, =0, simulate the response of both
models to a constant torque of amplitude of 100 N-m applied for 0.01 seconds (basically a discretized
approximation of the unit impulse function). Show the response of both of the models using a scope.
Compare the responses of the system.
(d) Simulate the response of both models with a constant torque of amplitude of 1000 N-m applied for 0.01
seconds. Explain the differences between the simulations of the two models. Is the linear approximation
of the nonlinear pendulum model more accurate for the larger input, or the smaller input?
(40 points)
2

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