Question: 6- The figure shows a solar collector panel with a surface area of 2.97 m. The panel receives energy from the sun at a
6- The figure shows a solar collector panel with a surface area of 2.97 m. The panel receives energy from the sun at a rate of 1.5 kW. Thirty- six percent of the incoming energy is lost to the surroundings. The remainder is used to heat liquid water from 40C to 60C. The water passes through the solar collector with a negligible pressure drop. Neglecting kinetic and potential energy effects, determine at steady state the mass flow rate of water, in kg/min. rA=2.97 m Water in 1.5 EW Solar collector pened Water out at 40 C 36% loss at 60C Useful I data: Gas Molar mass- M-, kg/k mol Y = C/C Air 28.97 32 58 1.4 en 1.4 Butane (CH10) Nitrogen (N2) Methane (CH) 1.1 1.4 1.32 28 16 Universal gas constant 8.314 kJ / kmol. K 1 bar = 100 kPa For liquid waterh = 4.18 *t, kJ/kg where t in C Water density 1000 kg/m %3D
Step by Step Solution
3.47 Rating (154 Votes )
There are 3 Steps involved in it
To determine the mass flow rate of water follow these steps Step 1 Calculate the Energy Received by ... View full answer
Get step-by-step solutions from verified subject matter experts
