Question: This homework tests your ability to evaluate potential pipeline hazards. The following program is used as a model. It computes vehicle sales by large (>50000)

This homework tests your ability to evaluate potential pipeline hazards. The following program is used as a model. It computes vehicle sales by large (>50000) and small makes.

// WarRawWawRarSample.cpp : Sample program for Homework 5

#include

#include

#define makes 29

int main(int argc, char* argv[])

{

// Vehicle sales from

// http://online.wsj.com/mdc/public/page/2_3022-autosales.html#autosalesD

char makers[makes][12] = {

"GM", "Ford", "Chrysler", "Toyota",

"Honda", "Nissan", "Hyundai", "Mazda",

"Mitsubishi", "Kia", "Subaru", "Mercedes",

"Volvo", "Volkswagen", "Audi", "BMW",

"Porsche", "Fiat", "Tesla", "Jaguar",

"Land Rover", "Alfa Romeo", "Mini", "Smart",

"Ferrari", "Maserati", "Bentley", "Lamborghini",

"Rolls Royce"};

int sales[makes] = {

259557, 229739, 196526, 211125,

148829, 123861, 62213, 26195,

9674, 56508, 50380, 31825,

6168, 27112, 17801, 24951,

5410, 3045, 2900, 1087,

5188, 60, 4796, 466,

217, 1066, 110, 89,

79};

int i, j, large = 0, small = 0, largetot = 0, smalltot = 0;

const int lim = 50000;

for (i = 0; i < makes; i++) {

if (sales[i] > lim) {

large++;

largetot += sales[i];

}

else {

small++;

smalltot += sales[i];

}

}

std::cout << "Large:" << large << " vehicles:" << largetot << " Small:" << small << " vehicles:" << smalltot << ' ';

return 0;

}

On the following page, you will find the assembly code generated by the for loop above. List the type of hazard (WAR, WAW, RAW, RAR, Control, or none) and the data item causing the hazard in the spaces provided. These lines will be identified by an arrow ( ). Ignore lines marked N/A. The associated C++ code is interspersed. Note that the dword ptr [i] syntax refers to i as a variable, not as a subscript.

Address

Opcode

Operands

Hazard Type

Caused By

for (i = 0; i < makes; i++) {

010369EF

mov

dword ptr [i],0

N/A

010369F9

jmp

main+5EAh (01036A0Ah)

N/A

010369FB

mov

eax,dword ptr [i]

01036A01

add

eax,1

01036A04

mov

dword ptr [i],eax

01036A0A

cmp

dword ptr [i],1Dh

N/A

01036A11

jge

main+65Ah (01036A7Ah)

N/A

if (sales[i] > lim) {

01036A13

mov

eax,dword ptr [i]

01036A19

cmp

dword ptr sales[eax*4],0C350h

N/A

01036A24

jle

main+630h (01036A50h)

N/A

large++;

01036A26

mov

eax,dword ptr [large]

N/A

01036A2C

add

eax,1

N/A

01036A2F

mov

dword ptr [large],eax

N/A

largetot += sales[i];

01036A35

mov

eax,dword ptr [i]

01036A3B

mov

ecx,dword ptr [largetot]

01036A41

add

ecx,dword ptr sales[eax*4]

01036A48

mov

dword ptr [largetot],ecx

}

else {

01036A4E

jmp

main+658h (01036A78h)

N/A

small++;

01036A50

mov

eax,dword ptr [small]

01036A56

add

eax,1

N/A

01036A59

mov

dword ptr [small],eax

N/A

smalltot += sales[i];

01036A5F

mov

eax,dword ptr [i]

N/A

01036A65

mov

ecx,dword ptr [smalltot]

N/A

01036A6B

add

ecx,dword ptr sales[eax*4]

N/A

01036A72

mov

dword ptr [smalltot],ecx

}

}

01036A78

jmp

main+5DBh (010369FBh)

N/A

Which hazard type listed on the previous page (not none) is not really a hazard? ___________________

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