This is a C++ problem

Write a program to convert between integer bases using loops. o input: - A base to convert from. [range: 2 10] - Prompt the user for this value thenumber is not in this range, output a descriptive error message (to cerr) then prompt the user for this value again. (this requires a loop) An integer to convert. [range: 0 (210-1)] Prompt the user for this value (note: each digit must be less than the base. Validate this in the loop.) . If the number is not in this range, output a descriptive error message (to cerr) then prompt the user for this value again A target base to convert to. [range: 2 - 10] - Prompt the user for this value If the number is not in this range, output a descriptive error message (to cerr) then prompt the user for this value again. o output: the number represented in the target base Note. Display this number using decimal digits, e.g. 2345 will be displayed using the decimal value 2102 + 3 101 +4100 (place the decimal Power * 10 statement in the loop to generate the successive powers) testing of this program should show the same value when converted from one base to another and then back again. o Your typescript file demonstrating the o algorithm: 1. If the source base! 10, convert the source base value to decimal (base 10). multiply each digit of the input number by the base to it's respective power, e.g. the 2 in 2345 will be multiplied by 52 - use basePowerbase to generate each successive power of the source base . use value 10 to extract the rightmost digit use value 10 to strip off the rightmost digit from value 2. If the destination base-10, convert the decimal (base 10) value to the destination base, then represent the destination base value synthetically in decimal