This is a linear programming table and its optimal solution for product A, B, C, D

if we know the material's price is $8, should the company buy more material to expand the production's scope? if yes how much material should the company buy? and what if the material's price is $4?

A B C D 5 3 6 1 1 Constraint 4 450 2 120 2 300 Worker Equipment Material Profit 2 3 4 5 30 10 40 20 Iteration-4 C; 30 10 40 20 0 0 0 B CB XB *1 X2 X4 Si S2 S3 MinRatio X4 20 7.5 0 -0.5 0 1 0.05 0.75 -0.35 X3 40 30 0 1 1 0 -0.2 0 0.4 X1 30 45 1 0 0 0 0.3 -0.5 -0.1 Z= 2700 = 30 30 40 20 2 0 6 Z; Z - C; 0 20 0 0 2 0 6 Since all Z;-C;20 Hence, optimal solution is arrived with value of variables as : x1 = 45, x2 = 0, x3 = 30, X 4 = 7.5 = = Max Z = 2700