Question: This is a two-part question (if that's ok!): Given a collection of pairwise disjoint countable sets {A n : n N}, prove that the union

This is a two-part question (if that's ok!):

Given a collection of pairwise disjoint countable sets {An : n N}, prove that the unionA=nNAn is also countable by defining a bijection betweenNN and A in two ways:

(1) Assume for each n, there is a bijection fn : N An, and define the assignment F :NN A by F(n, m) = fn(m). How do I prove F is a function, that is one-to-one and onto?

(2) If I am again assuming for each n, there is a bijection gn : An N, how do I now prove that the assignment given below is a function, and is one-to-one and onto?:

G : A NN defined by for each x A, G(x) = (n, gn(x)) (where n is the index of the set where x An)

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