This is for Analytical Chemistry. I NEED help with this TONIGHT.PLEASE
Assume the range in which the human eye detects color change isfrom 10% to 90% of the indicator dye reacted. Write the balancedchemical equation for the acid dissociation; let “HIn” representthe color indicator. Make an ICE table showing either 10% or 90%dissociated and compute the pH range of color change of the givendye: Indicator Ka = 7.9 x 10-10 (0.8)

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change in P H 19 SOLUTION K In Base for 10 Ka 10 10 HIn H ... View the full answer