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function [root,iter,ea] = newtraph(func,dfunc,xr,es,maxit)

% Inputs:

%

%

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% Outputs:

%

if nargin

maxit=50; % sets the max interactions =50

end

if nargin

es=0.01; % step size .01

end

iter = 0; % iteration set to 0

while (1) % while loop for 1

xrold = xr; % sets the old gas to xr so we can change it later on and run through multiple iterations

xr = xr - func(xr)/dfunc(xr); % this is the formula for the newtraph

iter = iter + 1; % takes our iteration and adds one to the original to use as the next gues point

if xr~=0 % if then

ea = 100*abs((xr-xrold)/xr); % fiding the error

xrv(iter) = xr; %root vector storing to grab values later

eav(iter) = ea; %error vector storing to grab values later

inerv(iter) = iter; %iteration vector storing to grab values later

end

if ea = maxit % if error is greater or equal if true then set interations lessthen or equal to maxit. if not then stop

break % stopes statements from being executed after this point

end

end

root = double(xr);

subplot(2,1,1) % subplot makes it able to print multiple graphs on 1 window has 2 rows 1 column and 1 Position

plot(inerv,xrv)% plots with x,y axis

xlabel('iteration'); %label x

ylabel('root estimate'); %label y

subplot(2,1,2)% subplot makes it able to print multiple graphs on 1 window has 2 rows 1 column and 2 Position

plot(inerv,eav)% plots with x,y axis

xlabel('iteration'); %label x

ylabel('Error'); %labely

end

Lab 5 Homework 30 points Use the Newton-Raphson Method Code provided in lab. 1. To find the inverse of a number a, the following equation may be used: f(c) = a 0 F C where c is the inverse of a . Use the Newton-Raphson method of finding roots of equations, to find the inverse of a = 2.5 Lab 5 Homework 30 points Use the Newton-Raphson Method Code provided in lab. 1. To find the inverse of a number a, the following equation may be used: f(c) = a 0 F C where c is the inverse of a . Use the Newton-Raphson method of finding roots of equations, to find the inverse of a = 2.5