Question: This is question 3.65 (pg 317) from Book: Computer Systems: A Programmers Perspective (3rd Edition): The following code transposes the elements of an M M

This is question 3.65 (pg 317) from Book: Computer Systems: A Programmers Perspective (3rd Edition):

The following code transposes the elements of an M M array, where M is a constant by #define:

1 void transpose(long A[M] [M] {

2 long i, j;

3 for (i = 0; i < M; i++)

4 for (j = 0; j < i; j++) {

5 long t = A [i] [j];

6 A [i] [j] = A [j] [i];

7 A [j] [i] = t;

8 }

9 }

When compiled with optimization level -O1, gcc generates the following code for the inner loop of the function:

1 .L6

2 movq (%rdx), %rcx

3 movq (%rax, %rsi

4 movq %rsi, (%rdx)

5 movq %rcx, (%rax)

6 addq %8, %rdx

7 addq $120, %rax

8 cmpq %rdi, %rax

9 jne .L6

We can see that GCC has converted the array indexing to pointer code.

A. Which register holds a pointer to array element A [i] [j] ?

B. Which register holds a pointer to array element A [j] [i] ?

C. What is the value of M ?

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