Question: This is question 3.65 (pg 317) from Book: Computer Systems: A Programmers Perspective (3rd Edition): The following code transposes the elements of an M M
This is question 3.65 (pg 317) from Book: Computer Systems: A Programmers Perspective (3rd Edition):
The following code transposes the elements of an M M array, where M is a constant by #define:
void transpose(long A[M] [M] {
long i, j;
for (i = 0; i < M; i++)
for (j = 0; j < i; j++) {
long t = A [i] [j];
A [i] [j] = A [j] [i];
A [j] [i] = t;
}
}
Then compiled with optimization level -O1, gcc generates the following code for the inner loop of the function:
.L6
movq (%rdx), %rcx
movq (%rax, %rsi
movq %rsi, (%rdx)
movq %rcx, (%rax)
addq %8, %rdx
addq $120, %rax
cmpq %rdi, %rax
jne .L6
We can see that GCC has converted the array indexing to pointer code.
A. Which register holds a pointer to array element A [i] [j] ?
B. Which register holds a pointer to array element A [j] [i] ?
C. What is the value of M ?
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