Question: this is the driver code #include int wbitadd(const unsigned char w, const unsigned long m, const unsigned long n, unsigned long *result); int main() {

 this is the driver code #include int wbitadd(const unsigned char w,
const unsigned long m, const unsigned long n, unsigned long *result); int
main() { unsigned char w = 11; unsigned long m = 0xffff400;
unsigned long n = 0x400; unsigned long sum; int overflow; overflow =
!wbitadd(w,m,n,&sum); printf("%d-bit 0x%lx + 0x%lx = 0x%lx ",w,m,n,sum); if (overflow) printf("(overflows)"); putchar('
this is the driver code
#include

int wbitadd(const unsigned char w, const unsigned long m,

const unsigned long n, unsigned long *result);

int main() {

unsigned char w = 11;

unsigned long m = 0xffff400;

unsigned long n = 0x400;

unsigned long sum;

int overflow;

overflow = !wbitadd(w,m,n,&sum);

printf("%d-bit 0x%lx + 0x%lx = 0x%lx ",w,m,n,sum);

if (overflow)

printf("(overflows)");

putchar(' ');

return 0; 0
need help implementing this function

You are to implement a simple function with the following type declaration: long wbitadd (const unsigned char w, const unsigned long m, const unsigned long n, unsigned long *result); This function implements two's complement (signed) addition on the second and third arguments, which are interpreted as w-bit signed integers, where w is the first argument. The w-bit result is placed in the location pointed to by the fourth argument. The function returns 0 if the addition operation overflows, and 1 otherwise. In other words, the return value, interpreted as a boolean, indicates whether a valid result has been returned, so it can be used in the following way: if (wbitadd (width, addendi, addenda, &sum)) { // sum contains the valid result } else { // handle overflow ) The preconditions for this function, which you may assume are satisfied, are as follows: PO 1

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