Question: this only the msq(dont provide solution) plz do all the questions 1) Dam baffle is used 2 points During subcooling process in a condenser During

this only the msq(dont provide solution)
plz do all the questions
this only the msq(dont provide solution)plz do all the questions 1) Dam
baffle is used 2 points During subcooling process in a condenser During
desuperheating process in a condenser During condensation process in a condenser O

1) Dam baffle is used 2 points During subcooling process in a condenser During desuperheating process in a condenser During condensation process in a condenser O None of the above 2) Corrosive vapor is allocated to 2 points Shell side of the condenser Tube side of the condenser O Any of the above None of the above 3) Which is not true for condenser? 2 points Large duty condenser should be placed horizontally O Baffle spacing is equal to shell diameter Baffle cut is horizontal None of the above 4) Saturated vapor enters to vertical shell and 4 points tube condenser at 120C and condenses in tube side where 90% condensation takes place. The condensate flow rate is 10000 kg/h. In this condenser 100 tubes of 25 mm OD, 21 mm ID and 4.88 m long are used. Determine tube side heat transfer coefficient using following graph: Given: 1L = 928 kg/m?, rv = 1.62 kg/m, HL=0.0002 kg/m s, ke=0.837 W/mC, Cp=4.187 kJ/kg C and g = 9.81 m/s2 O 8214 W/mK 10840 W/mK 12451 W/ mK O 14562 W/ mK 5) 4 points For .No. 4, determine tube side heat transfer coefficient using following expressions: - -0.021 =1+ 18249 W/mK 10840 W/mK O 12451 W/mK O 14562 W/mK 6) For Q.No. 4, the final tube side heat transfer 1 point coefficient is O 14562 W/ mK 10840 W/mK O 12451 W/mK O 18249 W/mK 7) 50000 kg/h of corrosive vapour is to be4 points condensed. The vapour enters the condenser saturated at 80C where complete condensation is achieved. The enthalpy of the vapour is 700 kJ/kg and the condensate 300 kJ/kg. Cooling water is available from 25C to 40C. In this condenser 25 mm OD, 21 mm ID and 4.88 m long are arranged in triangular pitch. Given: 1-2 pass, Vassumed = 800W/m2, Prandit no. 1.4, baffle cut = 25%, L = 928 kg/m, rv = 1.62 kg/m?, ML = 0.0002 kg/m s, Hv = 0.000008 kg/m s, ku = 0.837 W/m C, Cp = 4.187 kJ/kg C and g = 9.81 m/s? Determine tube side heat transfer coefficient using following equation: (a), -0.76, PA6 Pome* WAN O 14566 W/m2C 011376 W/m C 9463 W/m2C O 17556 W/m2 c 8) 4 points For O No. 7, determine tubeside hest transfer coefficient using tollowing expressions *;-64021 ) Brent plus O20506 W/m C O 18453 W/mC O29123 W/m2C O 10756 W/m2C 9) For Q.No. 7, the final tube side heat transfer point coefficient is O 11356 W/mC O 17556 W/mC O29123 W/m2C O20506 W/m2c 10) Heat transfer coefficient is more for 2 points O Film wise condensation Drop wise condensation O Both are equal None of the above 11) 2 points In the following expression, value of N.' is (he), = 0.95k_[P2(2-P.)&$ ;-18 Mir Decimal number Complete number As obtained O None of the above 12) For pure saturated vapour-water system in 2 points condenser, mean temperature difference is OLMTD OLMTD with FT correction factor Temperature difference of two fluids None of thoshow

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