This program fails when two strings are equal.

Please fix this problem by adding a "else" statement.

import java.util.Scanner;

/**

* This Program will sort the inputs lexicographically

*

* @author Jay

* @version 01-28-2020

*/

public class P3_16

{

public static void main(String[] args)

{

// representations of strings

String top = "";

String middle = "";

String bottom = "";

Scanner input = new Scanner(System.in);

System.out.println("Enter the 1st string: ");

String firstString = input.nextLine();

System.out.println("Enter the 2nd string: ");

String secondString = input.nextLine();

System.out.println("Enter the 3rd string: ");

String thirdString = input.nextLine();

// This will compare the first strings to the other two strings

if ((firstString.compareTo(secondString) < 0) && (firstString.compareTo(thirdString) < 0))

{

top = firstString;

if (secondString.compareTo(thirdString) < 0)

{

middle = secondString;

bottom = thirdString;

}

else if (secondString.compareTo(thirdString) > 0)

{

middle = thirdString;

bottom = secondString;

}

}

else if ((secondString.compareTo(firstString) < 0 ) && (secondString.compareTo(thirdString)< 0 ))

{

top = secondString;

if (firstString.compareTo(thirdString) < 0 )

{

middle = firstString;

bottom = thirdString;

}

else if (firstString.compareTo(thirdString) > 0 )

{

middle = thirdString;

bottom = firstString;

}

}

else if ((thirdString.compareTo(firstString) < 0 ) && (thirdString.compareTo(secondString)< 0 ))

{

top = thirdString;

if (firstString.compareTo(secondString) < 0 )

{

middle = firstString;

bottom = secondString;

}

else if (firstString.compareTo(secondString) > 0 )

{

middle = secondString;

bottom = firstString;

}

}

System.out.println();

System.out.println(top);

System.out.println(middle);

System.out.println(bottom);

}

}