Consider the equation of the line through X(1,-1,1) and Y(-3,3,2)

This question is abeut determining whether a given peint lies on a line In the vector form of the equation, r = - OX +tXY: (a) Enter OX in the form (1,2,3). (b) Enter XY in the form (1,2,3). (c) Use the vector form of the equation to find the parametric form. Enter in the form (10+20*t,11-30*t, 12+50*t) (so it is just a vector, not an equati on with an = sign). Use t as the variable. It must be the form that comes from the vector equation above, not an equivalent one. Using the parametric form above, solve for t in terms of z, t in terms of y and t in terms of z. Enter these three expressions below. (Note: when these three expressions are set equal to each other they make up the cartesian form of the line). (d) Enter the expression that involves z. Don't enter t=, (e) Enter the expression that involves y. () Enter the expression that involves z. Let R be the point R(-11,11,6). Calculate the numerical value of the three expressions in the cartesian form of the equation when the values from R are substituted in: (g) The expression that involved z: Number (h) The expression that involved y: Number ) The expression that involved z: Number 0) Is R on the line XY? Yes No