This question requires a numerical answer. Do NOT include units or use scientific notation in your answer (Canvas does not understand these). DO include a negative sign if appropriate. Give your answer to the nearest whole number (no decimal places). Consider the combustion of glucose: C6H1206(s) + 602 (g) -- > 6CO2(g) + 6H2O(1) AH = -2801 kJ If the enthalpy of formation for CO2(g) is 393.5 kJ/mol and for H2O(l) it is = -285.8 kJ/mol, calculate the enthalpy of formation for glucose (C6H120) in kJ/mol