Question: Thomas starts at the position (2, 3) m in the x-y plane and undergoes the following displacements: d = (3,-2) m, d2 = (-6,-8)

Thomas starts at the position (2, 3) m in the x-y plane

Thomas starts at the position (2, 3) m in the x-y plane and undergoes the following displacements: d = (3,-2) m, d2 = (-6,-8) m, and d3 = (-2,-5) m. What is Thomas's final position in the x-coordinate?

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To find Thomass final position in the xcoordinate we need to add up the xcomponents ... View full answer

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