three ions $,$ and $\{$:$C{l}^{-})$influence the transmembrane potential, $V_m.$

$1$A$)$ Noting that the net current across the membrane is zero, use the equation for the flux of charged solutes

across charged membranes to show that the transmembrane voltage potential is given by:

$V_m=-\frac{RT}{F}ln[\frac{P_{K^{+}}{C}_{K_L^{+}}+P_{N{a}^{+}}{C}_{N{a}_L^{+}}+P_{C{l}^{-}}{C}_{C{l}^{-}}{?}_0}{P_{K^{+}}{C}_{K_0^{+}}+P_{N{a}^{+}}{C}_{N{a}_0^{+}}+P_{C{l}^{-}}{C}_{C{l}^{-}}{?}_L}]$

In the above equation, $P_i$ refers to the permeability of each ion through the membrane and is given by $P_i=$

$\frac{{}_i{D}_{ij}}{L}.$ Subscripts $0$ and $L$ denote the concentrations of $C_i$ in the extracellular and intracellular spaces,

respectively.