Three points on a shiny metallic surface is given X(3,0,5), Y(16,0,7) and Z(10,0,10). The light vector is L=-i+2j-k and the viewing vector is given by V=i+1.5j+0.5k. Assuming that there is only one object and that is illuminated by a single light source, calculate the resultant intensity. Take kd=0.5, ka=0.3 and the same for specular reflection W(theta) is 0.85. The value of n for specular reflection is 5. Assume Ia=1, Il=10, and neglect any intensity attenuation.

Answer rating: 100% (QA)

Here three points on the shiny metallic surface are given as X 300 Y 1607 ... View the full answer