to differentiate.

$y=(3-x^2)(x^{3}9x7)$

a$.$ Apply the Product Rule. Let $u=3-x^2$ and $v=x^{3}9x7.$

$($:$\frac{d}{dx}(uv)=(3-x^2)()(x^{3}9x7)\}$

b$.$ Multiply the factors of the original expression, $u$ and $v,$ to produce a sum of simpler te

$y=$

Find y$\text{'}$

$y^{\text{'}}=$