To do this, you can use the Inverse Transform Sampling Method for random number generation from...

 

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To do this, you can use the Inverse Transform Sampling Method for random number generation from an arbitrary continuous distribution having an inverse. For a continuous random variable, X, having distribution Fx (x), it is possible to generate random deviates of X by forming Fx¹(u), where u is a random number from a uniform distribution on [0,1]. MC 3.10.6 After determining n analytically from problem 3.10.6, sample n values repeatedly from the distribution of Y. You will use the approach above, first finding the distribution function and then using the inverse distribution evaluated at a random uniform value on [0,1] to generate a random deviate for Y. For each of the repetitions of n values, sort the y values and identify the minimum y[1] for comparison to to 0.2. Compute the sample proportion in 1000 trials of n values to see if the P(Ymin<0.2)>0.9. If your computed n is correct, the probability should be very close to 0.9. To do this, you can use the Inverse Transform Sampling Method for random number generation from an arbitrary continuous distribution having an inverse. For a continuous random variable, X, having distribution Fx (x), it is possible to generate random deviates of X by forming Fx¹(u), where u is a random number from a uniform distribution on [0,1]. MC 3.10.6 After determining n analytically from problem 3.10.6, sample n values repeatedly from the distribution of Y. You will use the approach above, first finding the distribution function and then using the inverse distribution evaluated at a random uniform value on [0,1] to generate a random deviate for Y. For each of the repetitions of n values, sort the y values and identify the minimum y[1] for comparison to to 0.2. Compute the sample proportion in 1000 trials of n values to see if the P(Ymin<0.2)>0.9. If your computed n is correct, the probability should be very close to 0.9.

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For the random fyy e the distribution Y Fyy fyydy variable Y the pdf is y ... View the full answer