To select an appropriate capacitor and inductor for a buck-boost converter, we need to consider the following parameters: the output voltage ripple, the peak energy stored in the inductor, and the nominal operating conditions. 1. Capacitor Selection: The output voltage ripple (V) is related to the output capacitor (C), the load current (I), and the switching frequency (f) of the converter. The relationship can be expressed as: V = I / (f * C) To ensure that the output voltage ripple is less than 10mV (0.01V), we can rearrange the formula to solve for C: C = I / (f * V) Assuming a load current of 1A and a switching frequency of 100kHz (common values for buck-boost converters), we can substitute these values into the formula: C = 1A / (100kHz * 0.01V) = 1F So, a capacitor of at least 1F would be needed to ensure that the output voltage ripple is less than 10mV. 2. Inductor Selection: The energy stored in the inductor (E) is related to the inductance (L) and the current through the inductor (I). The relationship can be expressed as: E = 0.5 * L * I^2 To minimize the peak energy stored in