Torques on Part A using the formula:

Torque=Frsin

0: 8.33*0.29* sin(-90)= -2.4157N/m (Clockwise direction)

1: 2.94*0.06*sin(90) = 0.1764N/m ( Counter Clockwise)

2: 5.39*0.41*sin(90) =2.2099 N/m( Counter Clockwise)

Hence T =F*rsin= (-2.4157)+(0.1764)+(2.2099)= -0.0294N/m

Part B:

0: 8.33*0.29* sin(-90)= -2.4157 (clockwise)

1: 12.7*0.06*sin(90) = 0.762 (counterclockwise)

2:14.7*0.41*sin (90) = 6.0271 (counterclockwise)

3: 4.90*0.15*sin(-90) =-0.735. (clockwise)

4:15.2*0.26*sin (-90) = -3.952. (clockwise)

Torque =F*rsin (-90) == -0.3137 N/m

what is % discrepancies of the torque using the formula

% Discrepancy = |total| / |i| x 100%