Question: Total Floor Load = 9 5 P . S . F Exterior Walls = 1 5 0 # / FT . For B 1 (

Total Floor Load=95 P.S.F
Exterior Walls=150 #/FT.
For B1(Reaction A is the lesser reaction if A and B or nol equal)
Wfloor=
B1 load due to floor load (lower case w)
Wperimeter=
B1 load due to perimeter load
(lower case w)
B1 spacing for floor load
B1Wtotal=
(Upper case W)
Bi Vmax=
B1Mmax=
B1 Length=
Total Floor Load = 9 5 P . S . F Exterior Walls =

Step by Step Solution

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Civil Engineering Questions!