Question: true or false TF17. All languages th DFSM at can be recognized by an NDFSM can be recognized by a T F 18. No infinite

true or false
 true or false TF17. All languages th DFSM at can be

TF17. All languages th DFSM at can be recognized by an NDFSM can be recognized by a T F 18. No infinite language is a regular language. 19. A DFSM can have zero, one, or multiple transitions from any state, on any symbol in . Note that - u . F 20. The configuration of a DFSM M is an element of K , where K is the set of states in M, and is the alphabet of L(M). TF 21. The pumping theorem cannot be used to prove that a language is regular. T F 22. Setting the pumping length k to a literal value, such as 1 or 5, is not allowed in a T F 23. Given that w is the input to a DFSM M, it is always possible for M to process T F 24. pumping theorem proof. every symbol in w without visiting any state more than once all q20, xyz e L some q20, xyaz L some q20, xyz L. q20, xyaz L. 29. A pumping theorem proof always starts by defining a string w in terms of n, In a pumping theorem proof, you must show that for some value of y, and for T F 25. In a pumping theorem proof, you must show that for all values of y, and for T F 26. In a pumping theorem proof, you must show that for some value of y, and for TF 27. In a pumping theorem proof, you must show that for all values of y, and for all T F 28. In a pumping theorem proof, you cannot assume that lyl 1. T F (that is, n is the number of strings in L). where w e L, and n = 30, In a pumping theorem proof, it is possible that xz = . T F

Step by Step Solution

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Databases Questions!