Try $it$ yourself!

SET$-UP$ the definite integral$(s)$ and find the volume $of$ the solid generated when

the region bounded $by$ the indicated curves $is$ revolved about the indicated axis.

$1.y=x^2,x=3,$ and the $x-$axis;

$(a)$ about the $x-$axis,

$(b)$ about $x=3$

$1.y=x^2,y=9,$ and the $y-$axis;

$(a)$ about the $y-$axis,

$(b)$ about $y=9$

$3.y=-\sqrt[\phantom{2}]{9-x},$ the $x-$axis, and the $y-$axis;

$(a)$ about the $x-$axis, $(b)$ about the $y-$axis

$4.y=\sqrt[\phantom{2}]{81-x^2},$ the $x-$axis, the region $on$ the right side $ofx=7$; about $x-$axis