Question: t-Test: Two-Sample Assuming Unequal Variance Current Process New Process Mean 63.15 48.15 Variance 104.2394737 60.87105263 Observations 20 20 Hypothesized Mean Difference 0 df 36 t
t-Test: Two-Sample Assuming Unequal Variance
| Current Process | New Process | |
|---|---|---|
| Mean | 63.15 | 48.15 |
| Variance | 104.2394737 | 60.87105263 |
| Observations | 20 | 20 |
| Hypothesized Mean Difference | 0 | |
| df | 36 | |
| tStat | 5.220581451 | |
| P(T<=t) one-tail | 3.82255E-06 | |
| tCritical one-tail | 1.688297714 | |
| P(T<=t) two-tail | 7.64509E-06 | |
| tCritical two-tail | 2.028094001 |
- What is the hypothesis in this scenario?
- Did the new fuel process take less or more time? How do you know?
- In the scenario, did you conduct a one or two-tailed test?
- What is thep-value? (Remember to interpret what the E-06 means and round to 3 decimal places)
- Do you think (as Freddy does) that the result is not statistically significant?
- Do the results "prove" anything?
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