Tutorial Exercise An electron moving parallel to the x axis has an initial speed of 5.69 x 106 m/s at the origin. Its speed is reduced to 1.13 x 105 m/s at the point x = 2.00 cm. (a) Calculate the electric potential difference between the origin and that point. (b) Which point is at the higher potential? Part 1 of 4 - Conceptualize We assume that the electron is moving in a vacuum. Its speed is reduced because it is moving to a higher electric potential energy. Since its charge is negative, this means that it is moving to a more negative potential; that is, its starting position is at a higher potential (a higher voltage) than its final position. Part 2 of 4 - Categorize We use the energy version of the isolated system model to equate the energy of the electron-field system when the electron is at x = 0 to the energy when the electron is at x = 2.00 cm. The unknown potential difference is AV. Part 3 of 4 - Analyze (a) The electron-field system is isolated, so by conservation of energy, we have AK + AU = 0, wh