Tutorial Exercise

Evaluate the integral by making the given substitution.

${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}{x}^2\sqrt[\phantom{2}]{x^{3}22}dx,u=x^{3}22$

Step $1$

We know that if $u=f(x),$ then $du=f^{\text{'}}(x)dx.$ Therefore, if $u=x^{3}22,$ th $du=dx.$

Step $2$