Tutorial Exercise Evaluate the integral using the following values. L x3 dx = 1484, Lx dx dx = 28, dx = 4 dx 2 Step 1 Now use the following to evaluate the integral L(-1) +1 dx. By basic integration rules, we have Love kf(x) dx = k k and a f(x) dx f(x) dx + + L 9(x) g(x) dx + h(x) x h(x) dx. [f(x) + g(x) + h(x L [F(x) - g(x) + h(x)] dx = [ f(x) Step 2 Therefore, L (x- 8x + 1) Step 3 1 2 2 Now substitute dx 3 dx 8 8 dx + 1 dx. x3 dx = Lx d dx = and dx = in the equation Then, 1 dx = x3 dx-8 x dx + 1 dx. 2