Tutorial Exercise In the figure below, the current in the long, straight wire is I, = 4.30 A and the wire lies in the plane of the rectangular loop, which carries a current I2 = 10.0 A. The dimensions in the figure are c = 0.100 m, a = 0.150 m, and f = 0.685 m. Find the magnitude and direction of the net force exerted on the loop by the magnetic field created by the wire. Part 1 of 4 - Conceptualize There are forces in opposite directions on the loop as shown in the diagram below. The magnetic field is stronger near the straight wire than it is farther away. By symmetry, the forces exerted on sides 2 and 4 (the horizontal segments of length a) are equal and opposite, adding to zero. The magnetic field in the plane of the loop is directed into the page to the right of I . By the right-hand rule, F = IL x B is directed toward the left for side 1 of the loop. A smaller force is directed toward the right for side 3. We expect the net force to be to the left with magnitude in the micronewton range. 2 Part 2 of 4 - Categorize We will use the equation for the magnetic force between two parallel wires applied to sides 1 and 3 of the loop to find the net force resulting from these opposing force vectors. Part 3 of 4 - Analyze For the total magnetic force for sides 1 and 3 of the loop, we have the following. F = F, + F2 = Mol1 2 (1 - 1)i = Mol142-a (471 x 10-7 N/A3) 2 Tt m 2 )