Question: Tutorial: Torque and statics III. Torque for non-perpendicular forces: 1 - Fperpendicular When the force is not perpendicular to the object it's trying to rotate,

 Tutorial: Torque and statics III. Torque for non-perpendicular forces: 1 -

Tutorial: Torque and statics III. Torque for non-perpendicular forces: 1 - Fperpendicular When the force is not perpendicular to the object it's trying to rotate, the torque it creates is equal to r = Frsine. F I= Fr sin 0 where F = force T - distance from point of rotation to where F is applied 9 - angle between the force and the object it's trying to rotate Notice what this means though: F sin 0 is the component of the force that is perpendicular to the object. This is the component of the force that is responsible for trying to get the object to rotation, perpendicular- F - Fsin0 I Fir where Fi = component of the force perpendicular to object it's trying to rotate F - distance from point of rotation to where F is applied Important: Don't forget about the sign. Counterclockwise torque is positive Clockwise infant negative A. The rod in the figure can rotate about its left end. The force shown is equal to 12 N and the length of the rod is 1.5 m. The torque caused by this force around the left end of the rod is (circle one): negative zero positive F b. Calculate the torque caused by the force F. Use Fir and don't forget to include the sign! Do NOT use Fr sin 0, you will get the question wrong! F2 40 G.A second force F - 12 N is added at the mid-point of the rod acting as shown. The torque caused by this force around the left end of the rod is (circle one) negative zero positive F que around the left end of the rod. Don't

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