Two $100$L CSTRs are arranged in parallel to process reactant A into two products, based upon the

two liquid phase reactions shown below:

$AB,(-r_A{)}_1=k_{A1}{c}_{A}mol{L}^{-1}$min$-1$

$A2C,(-r_A{)}_2=k_{A2}{c}_{A}mol{L}^{-1}$min$-1$

Where $k_{A1}=0\mathrm{.}035mi{n}^{-1}$ and $k_{A2}=0\mathrm{.}065mi{n}^{-1}.$ The reactions take place under isothermal and

isobaric conditions. The feed to each reactor contains equal amounts of A and an inert, a total

molar flow rate of $0\mathrm{.}4mo\frac{l}{m}in$ and feed rate $q_0$ of $4\mathrm{.}0\frac{L}{m}in.$

a$.$ What is the overall conversion and outlet concentrations of $A,B$ and $C?$

b$.$ If the reactors were arranged in series, rather than parallel, what do you expect would

happen to the values for the fraction conversion and concentrations of $A,B,$ and $C,$ relative

to the answers you calculated in part $($a$)?$ Provide a detailed explanation for your reasoning.