Two cover plates, each $7\mathrm{.}5$ mm thick, are welded to a W$460\backslash$times $74$ beam as shown. The allowable normal stress for both the beam and the plates is $\backslash$sigma all $=150$ MPa.

Given: w $=40\mathrm{.}5$ kN$/$m

S $=1460\backslash$times $103$ mm$3$ for W$460\backslash$times $74$

Moment of inertia of the beam $=333\backslash$times $106$ mm$3$

Determine the required value of the length of the plates. $($Round the final answer to two decimal places.$)=$ mRequired information

Two cover plates, each $7\mathrm{.}5mm$ thick, are welded to a W$46074$ beam as shown. The allowable normal stress for both the

beam and the plates is ${}_{\text{a}\text{l}\text{l}}=150$MPa.

Given: $w=40\mathrm{.}5k\frac{N}{m}$

$S=1460{10}^{3}m{m}^3$ for $W46074$

Moment $of$ inertia $of$ the beam $=333{10}^{6}m{m}^3$

Determine the required value of the length of the plates. $($Round the final answer to two decimal places.$)$

The required value of the length of the plates is

$m.$Required information

Two cover plates, each $7\mathrm{.}5mm$ thick, are welded to a W$46074$ beam as shown. The allowable normal stress for both the

beam and the plates is ${}_{\text{a}\text{l}\text{l}}=150$MPa.

Given: $w=40\mathrm{.}5k\frac{N}{m}$

$S=1460{10}^{3}m{m}^3$ for $W46074$

Moment $of$ inertia $of$ the beam $=333{10}^{6}m{m}^3$

Determine the required value of the width of the plates. $($Round the final answer to its nearest whole number$)=$ mm