Two different answers are given . Please indicate the correct answer for the first part of the question.

f(x) = le-A(x-0); x= 0,1,2, ...n (a) Let us find the maximum likelihood estimator of A and 0 based on a random sample of size n. n L(X) = [If (x;, 0) i=1 = le-(21-0) . Xe-(12-0) . . je-A(In -0) = \\"el-X(21-0)]+[->(x2-0)]+...+[-A(In-0)] = Amend EL-o(x; -0)(@) -The Pdf is given by f (x;8) = 254(X-8) The likelifeed function is given by it f ( Ti;) -A(xi-0) 71 L (2, D) -1(Xi-0) The log - likelifeed function is given by log L( 7,0) = nlog 2 - 7 2 (1i-0) --(1)