Question: Two particles move along the x- axis. For 0 S t S 8, the position of particle P at time t is given by xp(t)

Two particles move along the x- axis. For 0 S t

Two particles move along the x- axis. For 0 S t S 8, the position of particle P at time t is given by xp(t) = ln(t2 2t + 10). while the velocity of particle Q at time t is given by VQU') = :2 8! + 15. Particle Q is at position x = 5 at time t = O. (a) For 0 S t S 8, when is particle P moving to the left? (b) For 0 S t S 8, nd all times t during which the two particles travel in the same direction. (c) Find the acceleration of particle Q at time I = 2. Is the speed of particle Q increasing, decreasing, or neither at time t = 2 '? Explain your reasoning

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