Question: Two particles move along an x axis. The position of particle 1 is given by x = 6.00t2 + 3.00t + 2.00 (in meters and

Two particles move along an x axis. The position of particle 1 is given by x = 6.00t2 + 3.00t + 2.00 (in meters and seconds); the acceleration of particle 2 is given by a = – 8.00t (in meters per seconds squared and seconds) and, at t = 0, its velocity is 20 m/s. When the velocities of the particles match, what is their velocity?

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