Two test charges are located in the $x-y$ plane. If $q_1=-4\mathrm{.}100nC$ and is located at $x_1=0\mathrm{.}00m,y_1=0\mathrm{.}8800m,$ and the second

test charge has magnitude of $q_2=3\mathrm{.}600nC$ and is located at $x_2=1\mathrm{.}500m,y_2=0\mathrm{.}400m,$ calculate the $x$ and $y$ components, $E_x$

and $E_y,$ of the electric field vec$(E)$ in component form at the origin, $(0,0).$ The Coulomb force constant is

$\frac{1}{4lo{n}_0}=8\mathrm{.}99{10}^{9}N*\frac{m^2}{C^2}$