Two thin plastic rods, each of length L = 8.5 cm, are placed lengthwise along the...
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Two thin plastic rods, each of length L = 8.5 cm, are placed lengthwise along the x- axis with their ends D = 10.5 cm apart. Each rod carries a uniform linear charge density = 35 C/m. Refer to the figure. Patel, Simran-simran.patel@doane.edu -LDL dx FX -X dx 17% Part (a) Enter an expression for the magnitude of the electric force that a thin slice dx, of the first rod, located at x, exerts on a thin slice dx2 of the second rod, located at x2, in terms of defined quantities and the Coulomb constant. A 17% Part (b) Choose the correct expression for the magnitude of the electric force that the first rod exerts on the second rod. Find that expression by integrating your answer in part (a) over the lengths of both rods. Combine the resulting logarithms into a single logarithm. O O k 2 In k 2 In D(D+2L) (D+L) (D+L) D(D+2L) Submit & 2 (in (D+2)-In (+2) D+L Hint Feedback k 2 In (D+2L) D give up! Feedback: 0% deduction per feedback. Hints: 0% deduction per hint. Hints remaining: 1 17% Part (c) Calculate the magnitude of the electric force on the second rod due to the first rod, in newtons. A17% Part (d) What is the direction of the electric force on the second plastic rod? Take positive to indicate to the right. 17% Part (e) Calculate the magnitude of the force that the second rod exerts on the first rod, in newtons. 17% Part (f) What is the direction of the electric force that the second rod exerts on the first? Two thin plastic rods, each of length L = 8.5 cm, are placed lengthwise along the x- axis with their ends D = 10.5 cm apart. Each rod carries a uniform linear charge density = 35 C/m. Refer to the figure. Patel, Simran-simran.patel@doane.edu -LDL dx FX -X dx 17% Part (a) Enter an expression for the magnitude of the electric force that a thin slice dx, of the first rod, located at x, exerts on a thin slice dx2 of the second rod, located at x2, in terms of defined quantities and the Coulomb constant. A 17% Part (b) Choose the correct expression for the magnitude of the electric force that the first rod exerts on the second rod. Find that expression by integrating your answer in part (a) over the lengths of both rods. Combine the resulting logarithms into a single logarithm. O O k 2 In k 2 In D(D+2L) (D+L) (D+L) D(D+2L) Submit & 2 (in (D+2)-In (+2) D+L Hint Feedback k 2 In (D+2L) D give up! Feedback: 0% deduction per feedback. Hints: 0% deduction per hint. Hints remaining: 1 17% Part (c) Calculate the magnitude of the electric force on the second rod due to the first rod, in newtons. A17% Part (d) What is the direction of the electric force on the second plastic rod? Take positive to indicate to the right. 17% Part (e) Calculate the magnitude of the force that the second rod exerts on the first rod, in newtons. 17% Part (f) What is the direction of the electric force that the second rod exerts on the first?
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University Physics with Modern Physics
ISBN: 978-0321501219
12th Edition
Authors: Hugh D. Young, Roger A. Freedman, Lewis Ford
Posted Date:
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