Question: u _ o = ( h _ a * k * c ) / ( sinh ( k * H _ o ) , A

u_o =(h_a*k*c)/(sinh(k*H_o), A =(h_a*c)/sinh(k*H_o), c^2= g*tanh(k*H_o)/k , with k=2pi/wavelength. H_o =5m, wavelength=400 m, and h_a =0.04 m. Solve for C, A and u_o. and then plot the properties of u(x,y,t) as a function of y for x =0 and kct =0, pi/4, pi/2,3pi/4, pi, and etc up to 2pi. Comment on the pattern you see. Derive a form for bottom shear stresse tau_o. Show how this vaies in time when x=0. plot together with the plot of u_pb/u_o. knowing that u = u_o{cos[k(x-ct)]-(e^(-beta*y))*cos[k(x-ct)+ beta*y]}

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