Unix/Linux Questions Help Please

Question 1: For the following script: for i in 3 4 do echo $i done 1. Make a function name Question1 (no space between Question and 1). 2. Make this example as in the body of this function. 3. Call this function twice. Note that calling the function twice does not mean you run the script twice. Answer

The script is:

The output and description is:

Question 2: a=2 b=3 echo "2 + 3 = $((a+b))" 1. Make a function named Question2 2. Copy this script in the body of the function. 3. Make the variable: a to be local. 4. Call the function. 5. After the call add the instruction: echo "2 + 3 = $((a+b))" 6. Run the program. 7. Why the second output is not correct? Answer

The script is:

The output and description is:

Question 3: p=1 for ((i=2; i <= 3; i++)) do p=$((p * i)) done echo "2 * 3 = $p" 1. Name the function Question3. 2. Remove the first line (that is: p=1) and write it before the definition of the function. 3. Except the first line (that is p=1) copy the rest of the lines into the body of the function. 4. Call the function twice. 5. Why the value of the variable p in the second line of the output is incorrect? Answer

The script is:

The output and description is:

Question 4: p=1 for ((i=2; i <= 3; i++)) do p=$((p * i)) done echo $p 1. Name the function Question4. 2. Copy the all the above lines into the body of the function. 3. Make the variable p to be local. 4. Replace the instruction: echo $p by an appropriate return instruction to return the value of the variable: p 5. Call the function. 6. After the call display the value of p. Answer

The script is:

The output and description is: