urgent help asap EMERGENCY .

Given below a Point-to-point communication trace taken by Wireshark a network protocol analyzer software.

ETHER: ----- Ethernet Header -----

ETHER: Packet 3 arrived at 11:42:27.64

ETHER: Packet size = 64 bytes

ETHER: Destination = 8:0:20:18:ba:40

ETHER: Source = aa:0:4:0:1f:c8

ETHER: Ethertype = 0800 (IP)

IP: ----- IP Header -----

IP: Version = 4

IP: Header length = 20 bytes

IP: Type of service = 0x00

IP: x xx. .... = 0 (precedence)

IP: ...0 .... = normal delay

IP: .... 0... = normal throughput

IP: .... .0.. = normal reliability

IP: Total length = 40 bytes

IP: Identification = 41980

IP: Flags = 0x4

IP: .1.. .... = do not fragment

IP: ..0. .... = last fragment

IP: Fragment offset = 0 bytes

IP: Time to live = 63 seconds/hops

IP: Protocol = 6

IP: Header checksum = af63

IP: Source address = 163.173.32.65

IP: Destination address = 216.58.207.4

IP: No options

TCP: ----- TCP Header -----

TCP: Source port = 1368

TCP: Destination port = 25 (SMTP)

TCP: Sequence number = 143515262

TCP: Acknowledgement number = 3128387273

TCP: Data offset = 20 bytes

TCP: Flags = 0x10

TCP: ..0. .... = No urgent pointer

TCP: ...1 .... = Acknowledgement

TCP: .... 0... = No push

TCP: .... .0.. = No reset

TCP: .... ..0. = No Syn

TCP: .... ...0 = No Fin

TCP: Window = 32120

TCP: Checksum = 0x3c30

TCP: Urgent pointer = 0

TCP: No options

Analyse the above trace and indicate the following:

1. The protocol used in each of the following layers: Data Link, Network, Transport and Application. [2]
2. Source and destination MAC addresses [1]
3. Source and destination IP addresses. [1]
4. Explain the value 0x10 shown in the flags field (highlighted in blue color in the trace) by indication the type of this captured message? [1]
5. Explain the meaning of the value shown in window size (highlighted in blue color in the trac? [1]