Use a one-dimensional array to solve the following program. Write a application that inputs six numbers [Keep the numbers in an array]. The numbers must be between 20 and 200, inclusive. If the number is not between 20 and 200, ask for another input. When a number is entered, display the number only if it is not a duplicate of a number already entered. If it is a duplicate of a number already entered, display a message that the number is a duplicate number and ask for another input. Provide for the worst case in which all six numbers are different. Display the complete set of unique values input after the user enters each new value. UPLOAD Duplicate.java

I typed in the following code. Is this correct?

// Duplicate.java

// Importing packages

import java.util.Scanner;

public class Duplicate {

public static void main(String[] args) {

int counter[] = new int[201]; // placing the number limit

int arr[] = new int[6]; // indicating the user is inputtinng 6 numbers

int n, count = 0; // count of number being input

// create Scanner for input

Scanner sc = new Scanner(System.in);

// number must be between 20-200

while(true) {

System.out.println("Enter number between 20-200:");

// Enter the the next number

n = sc.nextInt();

// If number is not between 20-200

if(n<20 || n>20) {

System.out.println("Number must be between 20-200. Try again");

continue;

}

// using the while counter controlled loop if number is between 20-200

if(counter[n]==0) {

counter[n]=1;

arr[count++]=n;

}

// If number is a duplicate

else {

System.out.println("Number already exists. Try again");

continue;

}

// Break the statement if six integers are inputted

printArray(arr, count);

if(count==6);

break;

}

}

// Print arrays

private static void printArray(int[] arr, int n) {

for(int i=0; i

System.out.print(arr[i]+ "");

System.out.println();

}

}