Use Digital to create a circuit that implements a function f : B 10 B. The ten inputs should be named, respectively, X9, X8, X7, X6, X5, X4, X3, X2, X1, X0, the output should be named Y . The ten digits of the input are interpreted as a natural number between 0 and 1023 in the standard binary encoding (thus, 0, 0, 1, 0, 0, 0, 1, 1, 1, 0 represents 128+8+4+2 = 142). We consider the decimal representation to have four digits, A3, A2, A1, A0. Thus, in our example, we have A3 = 0, A2 = 1, A1 = 4, and A0 = 2. The output Y of the circuit should be 1 if at least two of the following three conditions are met: A2 = m, A1 = n, and A0 = p. Otherwise, the output should be 0

Can you explain to me how to implement this in Digital? At first, I have group the binary inputs into four group fromX9 toX6 , X5 to X2 and X1 to X0, I am confused on how to use binary-to-decimal converters too.