Use Newton method to find a solution accurate to within ${10}^{-5}$ for the given proble $2xcos2x-(x-2{)}^2=0$ for $2,3,$

Note: Wrong choices will be given negative marks.

a$.f^{\text{'}}(x)=2cos2x4xsin2x2(x-2)$

b$.2\mathrm{.}37068691766227$

c$.f^{\text{'}}(x)=2cos2x-4xsin2x-2(x-2)$

d$.2\mathrm{.}37068705682661$

e$.2\mathrm{.}37135851251495$

f$.)$