Question: Use Processing and Python Code: Your main goal is to write a function called inside_circle() according to the following specification: the function should have five

Your main goal is to write a function called inside_circle() according to the following specification: the function should have five separate numeric parameters: - x and y: the coordinates of an arbitrary point - circle_x and circle_y: the coordinates of the center of a circle - radius: the radius of the circle . the function should return a Boolean value: - True if the point (x,y) is inside the circle - False if the point x, y) is outside the circle To help test your code, we are providing you a starter file. All that you need to do is to complete the inside_circle() function definition in that file. You can then run the code and click on the canvas; the program will call your inside_circle() function to determine whether the point you clicked is inside or outside the circle Hint: Processing has a built-in function called dist() that returns the distance between two points (it is just an implementation of the distance formula that you may recall from math class). Think carefully about how such a function could be useful for solving this problem. 1 X = 75 2 y = 75 3 circle_X = 200 4 circle_y = 200 5 diameter = 150 11 14 15 16 7 def setup(): 8 size(500, 500) 9 fill(o) 10 stroke (255) textSize(72) 12 13 def draw(): background (0) global circle_x, circle_y, diameter, x, y fill(0) 17 ellipse(circle_x, circle_y, diameter, diameter) 18 fill(255) 19 ellipse(x, y, 5, 5) 20 21 if (inside_circle(x, y, circle_x, circle_y, diameter/2)): 22 text("Inside!", 10, 60) 23 else: 24 text("Outside!", 10, 60) 25 26 def inside_circle(x, y, circle_x, circle_y, radius): distance = ((x-circle_x) **2 + (y-circle_y)**2) 28 if distance >= diameter: return false 30 else: 31 return True 32 33 def mouseClicked(): global x, y 35 X = mouseX y = mouse 27 29 34 36
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